For finding maximum in a given range for an array , we need to construct a
seg tree of hight log(n).
So, for n queries out time complexity will be O(nlogn).

Now, if out query window size is known before hand, suppose j-i==K, how can
I reduce the complexity to (nlogK for finding an minimum for a given
range.)?
I am unable to code it actually. Can anyone please help.

PS: I want to solve it using RMQ only. So please reply considering that.

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