String = 1 0 1 1 0 1 1 1.
1. make the  array = 1 -1 1 1 -1 1 1 1
2. after second operation
array = 1 0 1 2 1 2 3 4
index = 0 1 2 3 4 5 6 7


a[1] = 0 -> [0,1] is a solution
a[0] = a[2] = a[4] so (0,4],(0,2],(2,4] are also solutions
a[3] = a[5] (3,5] is also a solution.

This Solution is O(n) in Both TC and SC
I have read this Question at many places but never seen a solution with O(n)
TC and O(1) space
where did you find these constraints ??

On Fri, Jul 1, 2011 at 4:21 PM, Anantha Krishnan <
[email protected]> wrote:

> Thanks.
>
> Can you plz explain for input 1 0 1 1 0 1 1 1.
>
> Also I want solution in O(n) TC and O(1) SC.
>
> Regards
> Anantha Krishnan
>
>
> On Fri, Jul 1, 2011 at 4:13 PM, sunny agrawal <[email protected]>wrote:
>
>> Take an array of size of the length of the string.
>> fill the array positions with one where string contains 1, and -1 where it
>> is 0
>>
>> Now for each i (1,n-1) perform the following operation
>> a[i] = a[i-1] + a[i]
>> now a[i] will contains sum of values from a[0] to a[i] in original array.
>>
>> Now only thing remains to find is two indexes in this array such that a[i]
>> = a[j]
>> where ever this condition is met ( i,j ] is a solution
>>
>> or if for some i a[i] = 0 in this case [0,i] will be a solution
>>
>> this can be done using hashing
>> hash the values in the array of size 2*n+1. as range of values is -n to n
>> and keep track of max interval.
>>
>>
>>
>> On Fri, Jul 1, 2011 at 3:22 PM, Anantha Krishnan <
>> [email protected]> wrote:
>>
>>> Given a string containing 0's and 1's. One would need to find the longest
>>> sub-string such that the count of 0's is equal to the count of 1's in the
>>> largest sub string.
>>>
>>> Regards
>>> Anantha Krishnan
>>>
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>>
>>
>>
>> --
>> Sunny Aggrawal
>> B-Tech IV year,CSI
>> Indian Institute Of Technology,Roorkee
>>
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-- 
Sunny Aggrawal
B-Tech IV year,CSI
Indian Institute Of Technology,Roorkee

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