Clarification : The number (count) is the number of elements between 1 and n
which are not evenly divisible by 5 prime numbers
and the result is the sum of all the numbers between 1
and n which are not evenly divisible by 5 prime numbers . Right???
For Example : if n=5 then
count ->2 (i.e 1 and 3 )
and result = 5
If I am wrong ,Please Correct me and give me the outputs expected
Thank You
Rajeev N B
On Tue, Jul 5, 2011 at 12:17 PM, shiv narayan <[email protected]>wrote:
> Write a program that accepts an input integer n, and calculates the
> number and sum of all the numbers between 1 and n (inclusive) that are
> NOT evenly divisible by ANY of the first 5 prime numbers (2,3,5,7,11).
> The program should print out a clearly labeled count and sum
> my code is : it is not giving correct result
>
> #include <iostream>
> #include<conio.h>
> using namespace std;
> int main()
> {
> int userInteger = 0;
> cout << "Enter A Number "<<endl;
> cin >> userInteger; // Ask For a number from the user
> if (userInteger > 0) // Is the number valid?
> {
> int result = 0;
> int prime[5] = { 2, 3, 5, 7, 11 };
> int a = 1, count = 0;
> while (a < userInteger) // Looping to user's input
> {
> int b = 0;
> while (b < 5) // Looping the prime numbers array
> {
> if (a % prime[b])
> {
> result += a; // If Not evenly divisible by prime number at index 'b'
> count++;
> }
> b++;
> }
> a++; // Increment the counter
> }
> cout << "Numbers Not evenly divisible by 5 prime numbers: " << count
> << endl;
> cout << "The Sum of numbers not evenly divisible by 5 prime numbers: "
> << result << endl;
> }
> getch();
> return 0;
> }
>
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