7 occurs 1 time...
so 8th digit is 1

On Wed, Jul 6, 2011 at 1:02 AM, aditya kumar
<[email protected]>wrote:

> in 70000000 : '0' occurs seven times and rst of the numbers occur zero
> times. i still dint get where i am wrong . plz explain me .
>
>
> On Wed, Jul 6, 2011 at 12:47 AM, L <[email protected]> wrote:
>
>> @aditya : I am wondering how many times 7 has occurred. Is it 1? Or is
>> it 0?
>>
>> Please take a moment before posting your solution, and think whether
>> it is write or wrong!
>>
>> On Jul 6, 12:11 am, aditya kumar <[email protected]> wrote:
>> > Q3. ans:70000000 i guess this is also a correct answer and no unique
>> soln as
>> > such
>> >
>> > On Wed, Jul 6, 2011 at 12:37 AM, aditya kumar
>> > <[email protected]>wrote:
>> >
>> >
>> >
>> >
>> >
>> >
>> >
>> > >  boolean palindromeCheck(String string)
>> > > {
>> > >  len=string.length();
>> > > if((string.length()>1))
>> > > {
>> > >  if((string.charAt(0)==string.charAt(len-1)))
>> > > {
>> > > str="";
>> > >  str=str+string.substring(1,(len-1));
>> > > palindromeCheck(str);
>> > > }
>> > >  else
>> > > {
>> > >  flag=false;
>> > > }
>> > >     }
>> > >  return flag;
>> > > }
>> >
>> > > THis also works fine if you dont want to use pointer
>> >
>> > > On Tue, Jul 5, 2011 at 9:37 PM, Azhar Hussain <[email protected]>
>> wrote:
>> >
>> > >> For Q4: I think this is the optimal code
>> >
>> > >> int recurPalin(char *start, char *end)
>> > >> {
>> > >>     if (end < start)
>> > >>         return true;
>> >
>> > >>     if (*start != *end)
>> > >>         return false;
>> >
>> > >>     return recurPalin(start+1, end-1);
>> > >> }
>> >
>> > >> -
>> > >> Azhar.
>> >
>> > >> On Tue, Jul 5, 2011 at 12:21 PM, vikas <[email protected]> wrote:
>> >
>> > >>> My program for Q4.
>> > >>>  // recursively find if a given string is palindrome
>> > >>>         bool IsPalindrome(string s, int start, int start2, bool
>> flag)
>> > >>>         {
>> > >>>             bool flag1 = flag;
>> > >>>             if (start >= 0 && start2 < (s.Length))
>> > >>>             {
>> > >>>                 char c1 = s[start];
>> > >>>                 char c2 = s[start2];
>> > >>>                 if (c1.Equals(c2))
>> > >>>                 {
>> > >>>                     if (start == 0 && start2 == s.Length - 1) { flag
>> =
>> > >>> true; }
>> > >>>                     if (IsPalindrome(s, start - 1, start2 + 1,
>> flag))
>> > >>>                     {
>> > >>>                         flag1 = true;
>> > >>>                     }
>> > >>>                 }
>> > >>>             }
>> > >>>             return flag1;
>> > >>>         }
>> >
>> > >>> while calling
>> > >>>            if (s.Length % 2 != 0)
>> > >>>             {
>> > >>>                 p.IsPalindrome(s, s.Length / 2 - 1, s.Length / 2 +
>> 1,
>> > >>> false);
>> > >>>             }
>> > >>>             else
>> > >>>             {
>> > >>>                 p.IsPalindrome(s, s.Length / 2 - 1, s.Length / 2,
>> false);
>> >
>> > >>>             }
>> >
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-- 
*Regards,*
*Piyush Kapoor,*
*CSE-IT-BHU*

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