a) Find min(A). - O(n)
b) Find max(A) - O(n)
c) Calculate sum of natural numbers starting from min(A) to max(A) -
O(n)
d) Calculate sum of all numbers in the array. - O(n)
e) If sum in step c) is not same as sum in step d), then elements are
not consecutive. If the sum is same, then they are consecutive.

Can anyone think of a counterexample that breaks the above algo.

On Jul 6, 8:25 am, Sathaiah Dontula <[email protected]> wrote:
> How about doing like this ?.
>
> Without loss of generality, I can assume that numbers starts from 1
> (if not, if it starts from ZERO, add by 1 to all the numbers,
>  if it is negative, find the min value, assume it is X, add by (-X)+1))
>
> Now assume numbers are M, compute the product of the numbers and compute M!
> and check if they are equal.
>
> does it work ?
>
> Thanks,
> Sathaiah
>
> On Wed, Jul 6, 2011 at 11:45 AM, Anantha Krishnan <
>
>
>
>
>
>
>
> [email protected]> wrote:
> > Check this
>
> > *int isconsecutive(int a[], int n) {*
> > *    if (n < 1) {*
> > *        return 0;*
> > *    }*
> > *    int max = a[0], min = a[0];*
> > *    int i = 0;*
> > *
> > *
> > *    int *hash = (int*) calloc(n, sizeof (int));*
> > *
> > *
> > *    //find min and max from the array*
> > *    for (i = 1; i < n; i++) {*
> > *        if (a[i] < min)*
> > *            min = a[i];*
> > *        else if (a[i] > max)*
> > *            max = a[i];*
> > *    }*
> > *
> > *
> >  *    if (max - min + 1 != n)*
> > *        return 0;*
> > *
> > *
> > *    for (i = 0; i < n; i++) {*
> > *        if (hash[a[i] - min + 1] == 1)*
> > *            return 0;*
> > *        hash[a[i] - min + 1] = 1;*
> > *    }*
> > *    return 1;*
> > *
> > *
> > *}*
> > *
> > *
> > *int main(int argc, char** argv) {*
> > *
> > *
> > *    int a[] = {-1, 0,1,2, 4, 3, 5};*
> > *    int n = sizeof (a) / sizeof (a[0]);*
> > *    printf("%d", isconsecutive(a, n));*
> > *
> > *
> > *    return (EXIT_SUCCESS);*
> > *}*
>
> > On Sat, Jun 25, 2011 at 1:14 AM, ross <[email protected]> wrote:
>
> >> Given an array, A, find if all elements in the sorted version of A are
> >> consecutive in less than O(nlogn).
> >> eg: A: 5 4 1 2 3 on sorting 1 2 3 4 5 all elements are consecutive --
> >> true
> >> A: 1 9 2 22 on sorting 1 2 9 22 all elements are NOT consecutive -
> >> false
>
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