I read that solution.
But the same doubt as Navneet which I think you also raised i one of your
posts on that thread

On Wed, Jul 6, 2011 at 10:34 PM, Navneet Gupta <[email protected]>wrote:

> Saurabh,
>
> I understood your solution but wonder if it is purely single traversal
>
> In affect, you have a second traversal when you are popping the
> strings from stack to form the reverse order string.
>
> Though the second activity is less than O(n) i.e. O(#words in string)
> Nice solution, this way we can also get rid of extra spaces easily in
> the actual string if that is also to be done.
>
> On Wed, Jul 6, 2011 at 10:16 PM, saurabh singh <[email protected]>
> wrote:
> > I have proposed my solution in one of the previous posts.Check the
> solution
> > there
> >
> > On Wed, Jul 6, 2011 at 10:10 PM, Tushar Bindal <[email protected]>
> > wrote:
> >>
> >> good job
> >> but how can this be done in one traversal as asked on the Adobe
> Interview
> >> Questions thread.
> >>
> >>
> >>
> >> On Wed, Jul 6, 2011 at 9:49 PM, Navneet Gupta <[email protected]>
> >> wrote:
> >>>
> >>> I think somebody on this thread has asked this question but i am not
> >>> able to find that.
> >>>
> >>> Question was if a string is like "my name is ram", then output should
> >>> be "ram is name my".
> >>>
> >>> Wrote the code for same, so sharing.
> >>>
> >>> #include<iostream>
> >>> #include<string>
> >>> using namespace std;
> >>>
> >>> void SwapStringChars(string &str, int pos1, int pos2)
> >>> {
> >>>        char ch = str[pos1];
> >>>        str[pos1] = str[pos2];
> >>>        str[pos2] = ch;
> >>> }
> >>>
> >>> void reverseString(string &str, int left, int right)
> >>> {
> >>>        for(int i = left ; i <= left + (right-left)/2 ; i++)
> >>>                SwapStringChars(str, i, right + left -i));
> >>> }
> >>>
> >>> void reverseWordsInString(string &str)
> >>> {
> >>>        char space = ' ';
> >>>        int len = str.length();
> >>>        int startIndex = 0, endIndex = 0;
> >>>        while(endIndex < len - 1)
> >>>        {
> >>>                while(str[endIndex] != space && endIndex <
> len)endIndex++;
> >>>                reverseString(str, startIndex, endIndex-1);
> >>>                startIndex = endIndex;
> >>>                while(str[startIndex] == space)startIndex++;
> >>>                endIndex = startIndex;
> >>>        }
> >>> }
> >>>
> >>> int main()
> >>> {
> >>>        string str;
> >>>        cout<<"\nEnter enter the string :";
> >>>        getline(cin,str);
> >>>
> >>>        //Reverse whole string at once
> >>>        reverseString(str, 0, str.length() - 1);
> >>>
> >>>        //Reverse Individual words in string
> >>>        reverseWordsInString(str);
> >>>        cout<<str;
> >>>        cin.get();
> >>>        return 0;
> >>> }
> >>>
> >>> --
> >>> Regards,
> >>> Navneet
> >>>
> >>> --
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> >>>
> >>
> >>
> >>
> >> --
> >> Tushar Bindal
> >> Computer Engineering
> >> Delhi College of Engineering
> >> Mob: +919818442705
> >> E-Mail : [email protected]
> >> Website: www.jugadengg.com
> >>
> >> --
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> >
> >
> >
> > --
> > Saurabh Singh
> > B.Tech (Computer Science)
> > MNNIT ALLAHABAD
> >
> >
> > --
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> >
>
>
>
> --
> Regards,
> Navneet
>
> --
> You received this message because you are subscribed to the Google Groups
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>
>


-- 
Tushar Bindal
Computer Engineering
Delhi College of Engineering
Mob: +919818442705
E-Mail : [email protected]
Website: www.jugadengg.com

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