hey i am getting size of empty struct 1.
check my code
#include<iostream>
#include<conio.h>
using namespace std;
struct empty{};
int main()
{
empty e;
int x=sizeof(e);
cout<<x;
getch();
return 0;
}
when i run this i get "1" as output
On Jul 6, 10:16 pm, Ashish Modi <[email protected]> wrote:
> @piyush:
> No,one can declare the variable of empty struct and access its address via
> pointer. So, when you are accessing address via pointer means some memory is
> allocated for that variable. But *sizeof()* operator returns *zero*?? why???
>
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> On Wed, Jul 6, 2011 at 10:38 PM, T3rminal <[email protected]> wrote:
> > @ashish
> > Most probably because empty struct in C have nothing associated with it.
> > They are as good as nothing. But empty classes in C++ can have member
> > functions. These functions need to be associated with object, having a
> > unique address, for that class. And unique address is not possible with
> > class of size 0 as already explained above.
>
> > --
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>
> --
> With Regards
> Ashish Modi
> 9423721478
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