On Thu, Jul 7, 2011 at 4:15 PM, Gaurav Tyagi <[email protected]> wrote:

> How about this ?
>
> 1. We construct a graph with these nodes.
> 2. We make an incoming edge on a node if it is created using some
> other node. Ex: 7=5+2. So 7 will have 1 incoming and 5 & 2 will have
> outgoing.
> 3. Select all the nodes which only have outgoing edges. These would be
> the actual distances between the nodes.
> 4. If the total number of nodes selected in step 3 are equal to
> milestones, then goto step 6.
> 5. Remove all the nodes from the graph which have only outgoing edges
> and goto step 3.
> 6. Rearrange the nodes in the correct order as per the distances
> given.
>
>

plz explain it wth example
ur procedure isnt clear
Durgesh

>
>
> On Jul 7, 9:23 am, Akshata Sharma <[email protected]> wrote:
> > There is a straight roads with 'n' number of milestones. You are given an
> > array with the distance between all the pairs of milestones in some
> random
> > order. Find the position of milestones.
> > Example:
> > Consider a road with 4 milestones(a,b,c,d) :
> > a <--- 3Km --->b<--- 5Km --->c<--- 2Km --->d
> > Distance between a and b = 3
> > Distance between a and c = 8
> > Distance between a and d = 10
> > Distance between b and c = 5
> > Distance between b and d = 7
> > Distance between c and d = 2
> > All the above values are given in a random order say 7, 10, 5, 2, 8, 3.
> > The output must be 3,5,2 or 2,5,3
>
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