i think DP has answer to this question

initialy compute the quality value of all the substrings of length 1,2,3
Ans[i][j] =
max(ans[i,j-2]+ans[j-1][j],ans[i,j-3]+ans[j-2][j],ans[i,i+1]+ans[i+2][j],ans[i,i+2]+ans[i+3][j])
something like that.

On Fri, Jul 8, 2011 at 1:31 AM, rajeev bharshetty <[email protected]>wrote:

> It scans 555 count=3(excellent group)  it will put in one group than 54
> since the count is one puts that in usual group quality =2*1 =2 ,
>
>
> On Fri, Jul 8, 2011 at 1:28 AM, Piyush Sinha <[email protected]>wrote:
>
>> @Rajeev...check ur logic for 55554
>>
>> On 7/8/11, rajeev bharshetty <[email protected]> wrote:
>> > So, I think first check for excellent groups then good and then usual to
>> > increase the quality.
>> > So to get excellent groups scan the string and keep a count of the
>> > contagious repeating elements ,if count==3 or count==2,then put in one
>> > group
>> > The same procedure for good and usual accord to constraints .
>> >
>> >
>> >
>> > On Thu, Jul 7, 2011 at 11:46 PM, Piyush Sinha
>> > <[email protected]>wrote:
>> >
>> >> You are given a String number containing the digits of a phone number
>> >> (the number of digits, n, can be any positive integer) . To help you
>> >> memorize the number, you want to divide it into groups of contiguous
>> >> digits. Each group must contain exactly 2 or 3 digits. There are three
>> >> kinds of groups:
>> >> • Excellent: A group that contains only the same digits. For example,
>> 000
>> >> or 77.
>> >> • Good: A group of 3 digits, 2 of which are the same. For example,
>> >> 030, 229 or 166.
>> >> • Usual: A group in which all the digits are distinct. For example, 123
>> or
>> >> 90.
>> >> The quality of a group assignment is defined as 2 × (number of
>> >> excellent groups) + (number of good groups)
>> >> Divide the number into groups such that the quality is maximized.
>> >> Design an efficient
>> >> algorithm to return the solution that maximizes the quality.
>> >>
>> >> --
>> >> *Piyush Sinha*
>> >> *IIIT, Allahabad*
>> >> *+91-8792136657*
>> >> *+91-7483122727*
>> >> *https://www.facebook.com/profile.php?id=100000655377926 *
>> >>
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>> *Piyush Sinha*
>> *IIIT, Allahabad*
>> *+91-8792136657*
>> *+91-7483122727*
>> *https://www.facebook.com/profile.php?id=100000655377926 *
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-- 
Sunny Aggrawal
B-Tech IV year,CSI
Indian Institute Of Technology,Roorkee

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