Algo :
Given array a[m] and b[2*m]

1. Shift the elements in the array b to the right half. Now the m
elements in the array b are from index m to 2m-1
2. Initialize i (iterator of array a[]) =0
    j (iterator of array b[]) = m
    k (iterator of the final array which is b[]) = 0
3.
while(1)
{
    if(i==m)
        break;
    else if(j==2m)
    {
        Copy the remaining elements from array a[] into array b[]
        Then break;
    }
    else
    {
        if(a[i] < b[j])
            b[k++]=a[i++];
        else
            b[k++]=b[j++];
    }
}


Time Complexity : O(m)
Space Complexity : O(1)


On Thu, Jul 7, 2011 at 1:49 PM, sunny agrawal <[email protected]> wrote:
> O(m) is always better than O(m^2) :) :P
> Simple merge sort
> hint : start from end of the arrays
>
> select the text in white font to see the hint :)
>
> On Fri, Jul 8, 2011 at 1:56 AM, Dumanshu <[email protected]> wrote:
>>
>> given two sorted arrays a[m]  b[2*m], each contains m elements only.
>> You
>> need to merge those two arrays into second array b[2*m].
>> anything better than O(m^2)????
>>
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>
>
> --
> Sunny Aggrawal
> B-Tech IV year,CSI
> Indian Institute Of Technology,Roorkee
>
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