Dave, Thanks for the reply but this solution is only valid when the burn rate is constant.
On Sat, Jul 9, 2011 at 9:11 AM, Dave <[email protected]> wrote: > Light the first string at both ends and the second string at one end. > When the first string burns out, 30 minutes will have transpired, and > 30 minutes's worth of the second string will remain. Light the second > end of the second string. It will burn out in 15 more minutes., making > a total of 45 minutes. > > Dave > > On Jul 8, 7:11 pm, "oppilas ." <[email protected]> wrote: > > You have 2 pieces of string of different, unspecified length, and some > > matches. Each piece of string takes exactly an hour to burn, but the burn > > rate is not constant. . The strings have different burn rates, and of > course > > you don't know the rates anyway. > > > > Using only the matches and the strings, measure 45 minutes. > > > > I have thought a lot but unable to find a solution for this problem. Can > > someone please try it. > > -- > You received this message because you are subscribed to the Google Groups > "Algorithm Geeks" group. > To post to this group, send email to [email protected]. > To unsubscribe from this group, send email to > [email protected]. > For more options, visit this group at > http://groups.google.com/group/algogeeks?hl=en. > > -- You received this message because you are subscribed to the Google Groups "Algorithm Geeks" group. To post to this group, send email to [email protected]. To unsubscribe from this group, send email to [email protected]. For more options, visit this group at http://groups.google.com/group/algogeeks?hl=en.
