For, [ n*n!+(n+1)*(n+1)!+.....+(n+m)*(n+m)! ] / (n+m+1)! = 1 - n!/(n+m+1)!
On Sun, Jul 10, 2011 at 1:00 PM, Puneet Ginoria <[email protected]>wrote: > n*n! = (n+1)! - n! > > > > -- > You received this message because you are subscribed to the Google Groups > "Algorithm Geeks" group. > To post to this group, send email to [email protected]. > To unsubscribe from this group, send email to > [email protected]. > For more options, visit this group at > http://groups.google.com/group/algogeeks?hl=en. > -- You received this message because you are subscribed to the Google Groups "Algorithm Geeks" group. To post to this group, send email to [email protected]. To unsubscribe from this group, send email to [email protected]. For more options, visit this group at http://groups.google.com/group/algogeeks?hl=en.
