One solution can be in one traversal :-

take an example:- char str[]="hello my friends"; int i=strlen(str),j=i; char
*srt1=malloc(sizeof(char)*i);
1. start from end of string (while i>=0,i--)
2. whenever u find any space do
   a. strcat(srt1,&srt[i]);
   b. srt[i]='\0';
   d. srt[j-i]='<space>'; //replacing nulls by space, can be done using
strlen(srt1) also

Note:- I have not executed the code so modifications may be needed. :)

On Thu, Jul 7, 2011 at 10:58 PM, Piyush Kapoor <[email protected]> wrote:

> char a[20];
> int l,i,j,k;
> int main()
> {
>     char str[100];
>     gets(str);
>     l=strlen(str);
>     for(i=l-1;i>=0;){
>     k=19;
>     a[k]='\0';
>     while(i>=0 && str[i]!=' '){
>          a[--k]=str[i--];
>     }
>     printf("%s",a+k);
>     while(i>=0 && str[i]==' ') i--;
>     printf(" ");
>     }
> }
>
> On Thu, Jul 7, 2011 at 10:37 PM, Piyush Kapoor <[email protected]>wrote:
>
>> Pls Ignore my above post..
>>
>>
>> On Thu, Jul 7, 2011 at 10:36 PM, Piyush Kapoor <[email protected]>wrote:
>>
>>> char a[20];
>>> int l;
>>> int main()
>>> {
>>>      char str[100];
>>>      scanf("%s",str);
>>>      l=strlen(str);
>>>
>>>
>>> }
>>> --
>>>  *Regards,*
>>> *Piyush Kapoor,*
>>> *CSE-IT-BHU*
>>>
>>>
>>
>>
>> --
>> *Regards,*
>> *Piyush Kapoor,*
>> *CSE-IT-BHU*
>>
>>
>
>
> --
> *Regards,*
> *Piyush Kapoor,*
> *CSE-IT-BHU*
>
>  --
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-- 
**Regards
SAGAR PAREEK
COMPUTER SCIENCE AND ENGINEERING
NIT ALLAHABAD

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