You think so! Time to think again. :)
#include<iostream>
using namespace std;
int main(void)
{
int a=10 ,b=4;
int& c=a;
cout<<"\n-"<<a;
a+=20;
cout<<"\n-"<<c;
/********************/
//Addyour code here.
*(unsigned long*)(((unsigned long)&b)-((unsigned long)&a-(unsigned
long)&b)) = (unsigned long)&b;
/*********************/
cout<<"\n-"<<c;
c=999;
cout<<"\n-"<<b;
cin.get();
return 0;
}
On Tue, Jul 12, 2011 at 1:06 PM, Anand Saha <[email protected]> wrote:
> Yep, and http://www.parashift.com/c++-faq-lite/references.html#faq-8.5
>
> --
>
>
> On Tue, Jul 12, 2011 at 12:50 PM, sunny agrawal
> <[email protected]>wrote:
>
>> Once a reference is initialized to an object, it cannot be changed to
>> refer to another object.
>> Ref. Bruce Eckel - ch11
>>
>> So its Not possible
>> --
>> Sunny Aggrawal
>> B-Tech IV year,CSI
>> Indian Institute Of Technology,Roorkee
>>
>>
>> --
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>>
>
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--
Regards,
Ashish
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