@shady...if modfying is not allowed....in that case i think O(n^2) is the
only option left with us...sorting can't be used in that case...

On Wed, Jul 13, 2011 at 9:01 PM, shady <[email protected]> wrote:

> @nicks so many problems could be solved in O(n) but it is very difficult to
> find a hashing function where there is no collision...
> and if we sort the list, we are modifying the list... which lets assume is
> not allowed............. then what to do ?
> suppose even if we know the index at which there are duplicates for every
> unique number even then the solution will be O(n^2) because you cant jump
> directly to that index
>
>
> On Wed, Jul 13, 2011 at 8:52 PM, nicks <[email protected]> wrote:
>
>> agree with saurabh.....merge sort will be the best.....using sorting
>> problem can be solved in O(nlogn)
>> else use hashing to solve in O(n)
>>
>> @shady.....ya that would be most obvious solution can be done easily in
>> O(n^2).
>>
>> On Wed, Jul 13, 2011 at 8:36 PM, shady <[email protected]> wrote:
>>
>>> what are the constraints ?
>>> if none then it could be done easily. O(N^2) solution
>>>
>>> On Wed, Jul 13, 2011 at 8:10 PM, Anika Jain <[email protected]>wrote:
>>>
>>>> how to remove duplicates from a linked list?? is it mandatory to sort
>>>> the list first?l
>>>>
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