@saurabh ....why in 2's complement form ?

On Thu, Jul 14, 2011 at 9:21 AM, saurabh singh <[email protected]> wrote:

> There is nothing wrong going wrong in the code shilpa.
> It specifies bit field
> a has now only 1 bit
> b has 2 bit.
> when u write t.a=6=(0110) it is stored as 0.
> while when u write t.b=2 it is stored as 10 which in 2's complement its -2.
> check size of t if you doubt me.
>
> On Thu, Jul 14, 2011 at 9:11 AM, shilpa gupta <[email protected]>wrote:
>
>> in second problem a:1 and b:3 means default initialization but not in c it
>> is D programming language but u may b trying to compile it with c complier
>> that's why it is showing wrong result..........if u will compile it with D
>> language compiler than it will print 6 and 2.....and if u will not
>> initialize them again with 6 and 2 then it will print 1 and 2
>>
>>
>> On Thu, Jul 14, 2011 at 8:27 AM, John Hayes <[email protected]>wrote:
>>
>>> Hey Guys, plz help me in getting these 2 C output problems
>>>
>>> 1st problem
>>>
>>>
>>> *#*include<stdio.h>
>>> int main()
>>> {
>>> short int a,b,c;
>>> scanf("%d%d",&a,&b);
>>>  c=a+b;
>>> printf("%d",c);
>>> return 0;
>>> }
>>>  INPUT-
>>> 1 1
>>>
>>> OUTPUT
>>> 1
>>>
>>> i am not getting why  1 is coming in the output.....what difference is
>>> using short making in the code ???
>>>
>>> Problem No. 2
>>> *
>>> *#include<stdio.h>
>>> main()
>>> {
>>> struct
>>> {
>>>  int a:1;
>>> int b:2;
>>> }t;
>>> t.b=6;
>>>  t.a=2;
>>> printf("%d %d",t.a,t.b);
>>> }
>>>
>>> OUTPUT
>>> 0 -2
>>>
>>> What does the statement  a:1 and b:1 mean and what are they doing.....i
>>> am seeing them first time ever...hence not able to get the output....if
>>> someone has any idea plz help  !!
>>>
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>>
>>
>>
>> --
>> shilpa gupta
>> b tech 2nd year
>> computer science and engineering
>> mnnit allahabad
>>
>>
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>
>
>
> --
> Saurabh Singh
> B.Tech (Computer Science)
> MNNIT ALLAHABAD
>
>
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