@Nicks *Problem 1* %d is used to take a signed integer as input. To take a short integer as input, use %hi. That way, you would get the correct answer as 2.
*Problem 2:* a:1 means that variable a is of width *1 bit* Similarly, b:2 means that b is of width *2 bits* b = 6 sets the two bits as 10, (last two bits of 110 considered), which is equal to -2 a = 2 sets the only bit as 0, (last bit of 10 considered), which is nothing but zero. Bit-fields like these however tend to be implementation-dependent and in the interest of portability should be avoided. t.b = 6 sets the last two bits of b as 10, which is -2 in 2's complement t.a = 2 sets the On Thu, Jul 14, 2011 at 1:18 AM, nicks <[email protected]> wrote: > Hey Guys, plz help me in getting these 2 C output problems > > *PROBLEM 1>.* > * > * > *#*include<stdio.h> > int main() > { > short int a,b,c; > scanf("%d%d",&a,&b); > c=a+b; > printf("%d",c); > return 0; > } > INPUT- > 1 1 > > OUTPUT > 1 > > i am not getting why 1 is coming in the output.....what difference is > using short making in the code ??? > > > *PROBLEM 2>.* > * > * > * > * > #include<stdio.h> > main() > { > struct > { > int a:1; > int b:2; > }t; > t.b=6; > t.a=2; > printf("%d %d",t.a,t.b); > } > > OUTPUT > 0 -2 > > What does the statement a:1 and b:1 mean and what are they doing.....i am > seeing them first time ever...hence not able to get the output....if someone > has any idea plz help !! > > -- > You received this message because you are subscribed to the Google Groups > "Algorithm Geeks" group. > To post to this group, send email to [email protected]. > To unsubscribe from this group, send email to > [email protected]. > For more options, visit this group at > http://groups.google.com/group/algogeeks?hl=en. > -- Gaurav Jain Associate Software Engineer VxVM Escalations Symantec Software India Pvt. Ltd. -- You received this message because you are subscribed to the Google Groups "Algorithm Geeks" group. To post to this group, send email to [email protected]. To unsubscribe from this group, send email to [email protected]. For more options, visit this group at http://groups.google.com/group/algogeeks?hl=en.
