@Anika
The code executes just all right.

@Abhishek
This is related to one of those irritating issues about precedence of
operators.
++ and * have the same precedence and have right-to-left associativity. So
your expression reads as

++(*b) = ++(*b)

RHS evaluates to 36 which gets stored in (*b) and gets incremented in place
to 37.
Output is *37*.

On Thu, Jul 14, 2011 at 12:02 PM, Anika Jain <[email protected]> wrote:

> compilation error lvalue required
> coz on lhs of ++*b=++*b is not a variable but a value
>
>
> On Thu, Jul 14, 2011 at 11:58 AM, abhishek kumar <
> [email protected]> wrote:
>
>> hi friends,
>> i have a doubt about this code. what will be its output and how.
>>
>> int a=35,*b;
>> b=&a;
>> ++*b=++*b;
>>
>>
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-- 
Gaurav Jain
Associate Software Engineer
VxVM Escalations
Symantec Software India Pvt. Ltd.

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