3 625/3=225 =15*15 On Thu, Jul 14, 2011 at 3:44 PM, shilpa gupta <[email protected]>wrote:
> its 5 > > > On Thu, Jul 14, 2011 at 3:38 PM, Piyush Sinha <[email protected]>wrote: > >> 5 >> >> >> On Thu, Jul 14, 2011 at 3:28 PM, anshul mehta <[email protected] >> > wrote: >> >>> by what least no. 675 be multiplied to obtain a no. which is a perfect >>> cube? >>> >>> -- >>> You received this message because you are subscribed to the Google Groups >>> "Algorithm Geeks" group. >>> To post to this group, send email to [email protected]. >>> To unsubscribe from this group, send email to >>> [email protected]. >>> For more options, visit this group at >>> http://groups.google.com/group/algogeeks?hl=en. >>> >> >> >> >> -- >> *Piyush Sinha* >> *IIIT, Allahabad* >> *+91-7483122727* >> * <https://www.facebook.com/profile.php?id=100000655377926> "NEVER SAY >> NEVER" >> * >> >> -- >> You received this message because you are subscribed to the Google Groups >> "Algorithm Geeks" group. >> To post to this group, send email to [email protected]. >> To unsubscribe from this group, send email to >> [email protected]. >> For more options, visit this group at >> http://groups.google.com/group/algogeeks?hl=en. >> > > > > -- > shilpa gupta > b tech 2nd year > computer science and engineering > mnnit allahabad > > > -- > You received this message because you are subscribed to the Google Groups > "Algorithm Geeks" group. > To post to this group, send email to [email protected]. > To unsubscribe from this group, send email to > [email protected]. > For more options, visit this group at > http://groups.google.com/group/algogeeks?hl=en. > -- Thanks and Regards *Karan Bagaria* *MCA Final Year* Training and Placement Representative *NIT Durgapur* -- You received this message because you are subscribed to the Google Groups "Algorithm Geeks" group. To post to this group, send email to [email protected]. To unsubscribe from this group, send email to [email protected]. For more options, visit this group at http://groups.google.com/group/algogeeks?hl=en.
