oops , didnt see the unsorted thing. complexity is mnlog(n) + mn log(m)

On Sat, Jul 16, 2011 at 4:23 PM, sagar pareek <[email protected]> wrote:

> sort all the arrays first O(nlogn)
>
> then use merge sort
>
>
> On Sat, Jul 16, 2011 at 3:43 PM, Ankur Khurana 
> <[email protected]>wrote:
>
>> Use divide and conquer. take 2 array at a time and .so you are merging two
>> array at a time.
>>
>> num_of_list=m;
>> length of list=n;
>>
>> while(num_of_list > 1)
>> {
>> while( (num of list where length = length_of_list) >2)
>> {
>> merge two lists of length (length_of_list);
>>
>> }
>> if(num_of_list %2==0)
>> num_of_list/=2;
>> else
>> num_of_list/=2+1;
>> length of list=n;
>>
>> }
>> (it is just a general idea , you have to take care of the left over list
>> every time , the check for that i havent posted)
>>
>> so time complexity is
>>
>>
>> 2*n* (m/2) + 2* 2n* (m/4) .............. log(m) times.
>>
>> so complexity is n*m*log(m)
>>
>>
>>
>>
>>
>> On Sat, Jul 16, 2011 at 2:43 PM, aseem garg <[email protected]> wrote:
>>
>>> Q2. Given m arrays of n size each, give an algorithm to combine these
>>> arrays into a single array with sorted elements. Also tell the time
>>> complexity of your solution.
>>> Aseem
>>>
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>
>
>
> --
> **Regards
> SAGAR PAREEK
> COMPUTER SCIENCE AND ENGINEERING
> NIT ALLAHABAD
>
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