ok i got it....
actually u written wrong that f/w and reverse traversal are running
parallel
u must wrote that f/w traversal inside reverse or vice versa

On Sat, Jul 16, 2011 at 10:35 PM, Dave <[email protected]> wrote:

> @Sagar: No problem. The algorithm would do only forward traversal
> steps until it got to root_>left, whereupon F + R = K.
>
> Dave
>
> On Jul 16, 11:40 am, sagar pareek <[email protected]> wrote:
> > @dave
> > what if the k= root->left + right most leaf ?
> > how ur algo works on it?
> >
> >
> >
> >
> >
> > On Sat, Jul 16, 2011 at 9:28 PM, Dave <[email protected]> wrote:
> > > @Noobcoder: To do it in O(n) without destroying the BST, do two
> > > inorder traversals simultaneously, one in the normal forward (left
> > > subtree first) direction and one in the reverse direction (right
> > > subtree first). Let the two current nodes have value F and R
> > > respectively. If F + R = K, return success. If F = R, return failure.
> > > If F + R < K, advance the forward traversal. Otherwise (F + R > K),
> > > advance the reverse traversal. To do the traversals simultaneously,
> > > you will have to use explicit stacks instead of recursion.
> >
> > > Dave
> >
> > > On Jul 16, 9:01 am, noobcoder <[email protected]> wrote:
> > > > Given a BST containing integers, and a value K. You have to find two
> > > > nodes that give sum = K.
> >
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> > --
> > **Regards
> > SAGAR PAREEK
> > COMPUTER SCIENCE AND ENGINEERING
> > NIT ALLAHABAD- Hide quoted text -
> >
> > - Show quoted text -
>
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-- 
**Regards
SAGAR PAREEK
COMPUTER SCIENCE AND ENGINEERING
NIT ALLAHABAD

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