sizeof long double is 12. So padding concept is perfectly working
On Mon, Jul 18, 2011 at 12:26 AM, aditya kumar <[email protected]
> wrote:
> struct st
> {
> char ch1;
> long double ld;
> }s;
> printf("%d",sizeof(s));
> //output : 24 (for 32-bit compiler)
> ->as i have mentioned above the behaviour is undefined in case of sizeof
> (struct)
> can any one explain me why the padding concept does not work here ??
>
> On Mon, Jul 18, 2011 at 12:13 AM, Parthiban <[email protected]> wrote:
>
>> @Abhi:
>> Answers:
>> 1. whenever a 'const' qualifier is added previously to a variable
>> declaration it means that the value of the variable is automatically
>> initialized to '0'(because of the 'auto' type of the const variable) and
>> cannot be changed in any of the following assignment statements to the const
>> variable.
>>
>> 2.
>> Here for the structure struct s1 since the entire structure is ending
>> within 8 bytes no padding is done which means
>> s1: [char a]
>> 1byte
>> but for the structure struct s2 consider the following:
>> s2: [ char a
>> 1byte
>> ------ int a-------
>> ------4bytes----]
>> so here the concept of padding comes to make all the variable aligned in
>> even boundaries and so the structure after aligning will look as:
>> s2: [ ------ char b----
>> ------4byte-----
>> ------ int a-------
>> ------4bytes----]
>>
>> so the size of strcut s2 will be 8bytes..........
>>
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>
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**Regards
SAGAR PAREEK
COMPUTER SCIENCE AND ENGINEERING
NIT ALLAHABAD
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