Then it can be done by taking the xor product of all number present in
the list & the number from 0 to 2^32,which would give the missing
number..  Example:- for list  (5 3 1 4) contain number from 1 to 5 ,2
is missing .Taking the xor of all elements and all number expected to
present i:e index from 1 to 5 ,

(5 3 1 4   1 2 3 4 5) xor will give 2 which is missing . space
complexityO(1), runtime complexityO(n)


On 7/18/11, ankit sambyal <ankitsamb...@gmail.com> wrote:
> I also interpreted it the same way
>
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