the 2.nd one is also working fine ...
check it out ..
http://www.ideone.com/ue96W

the given arguments are all correct .. bt since its returning a copy of it
to the main .. it'll work fine ...

On Mon, Jul 18, 2011 at 11:28 PM, sunny agrawal <[email protected]>wrote:

> Yes thats right but a small but obvious correction which holds good till
> you explicitly call free function or...
>
>
> On Mon, Jul 18, 2011 at 10:49 PM, Swathi <[email protected]> wrote:
>
>> In first 1, you are using malloc() so the memory will be allocated from
>> heap which holds good till end of your program.. In second case, the memory
>> will be allocated on the stack.. so once the function is exited, your stack
>> data will be released...
>>
>>
>> On Mon, Jul 18, 2011 at 9:49 PM, rj7 <[email protected]> wrote:
>>
>>> Can someone pls explain the difference between these two especially in
>>> terms of scope... one example i have come across is
>>>        1.
>>>        char *xxx(int n)
>>>        {
>>>        char *retbuf = malloc(25);
>>>        if(retbuf == NULL)
>>>                return NULL;
>>>        sprintf(retbuf, "%d", n);
>>>        return retbuf;
>>>        }
>>>
>>>        2.
>>>        char *xxx(int n)
>>>        {
>>>        char retbuf[25];
>>>        sprintf(retbuf, "%d", n);
>>>        return retbuf;
>>>        }
>>>
>>> First one is correct and the second one is wrong... why does the scope
>>> of retbuf extends to the calling function...
>>> am just a beginner so ignore the stupidity(if any).....
>>>
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>
>
>
> --
> Sunny Aggrawal
> B-Tech IV year,CSI
> Indian Institute Of Technology,Roorkee
>
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-- 
Shubham Maheshwari
ShubZz
O.o o.O

enJoY ...!!!

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