z is equal to 6 as both are post increment. However, if one of these was pre-increment, output would have been undefined.
On Jul 19, 9:39 am, sagar pareek <[email protected]> wrote: > you are using post increment which increments th evariable in next line :) > (except for the case of printf(); > > so here z=x++ + x++ will give you z=3+3 > and the two post increment will give you x+=2 > > i hope toy get it ) > > On Tue, Jul 19, 2011 at 8:17 AM, Vengadanathan > <[email protected]>wrote: > > > > > > > this is the program , > > #include<stdio.h> > > int main() > > { > > int z=0,x=3; > > z = x++ + x++; > > printf("%d %d",z,x); > > return 0; > > } > > > i though the output would be 7,5 , but when i ran the code it was > > 6,5 , can anyone tell me how this o/p is obtained . > > thanx in advance > > > -- > > You received this message because you are subscribed to the Google Groups > > "Algorithm Geeks" group. > > To post to this group, send email to [email protected]. > > To unsubscribe from this group, send email to > > [email protected]. > > For more options, visit this group at > >http://groups.google.com/group/algogeeks?hl=en. > > -- > **Regards > SAGAR PAREEK > COMPUTER SCIENCE AND ENGINEERING > NIT ALLAHABAD- Hide quoted text - > > - Show quoted text - -- You received this message because you are subscribed to the Google Groups "Algorithm Geeks" group. To post to this group, send email to [email protected]. To unsubscribe from this group, send email to [email protected]. For more options, visit this group at http://groups.google.com/group/algogeeks?hl=en.
