There is NO universal way of doing this; every compiler does it differently,
in its own ways.
The problem here is that the above code changes the value of variable `i'
many times between two sequence points. So you cant be sure as to what value
`i' holds at what time!!!

For more insight and a better explanation see
http://c-faq.com/expr/evalorder2.html
To know more about the sequence points in a C program see
http://c-faq.com/expr/seqpoints.html

On Fri, Jul 22, 2011 at 4:07 PM, rajeev bharshetty <[email protected]>wrote:

> Some more explanation taking an example will be helpful
> take the example in the program.
>
> Thanks
>
>
> On Fri, Jul 22, 2011 at 4:03 PM, Prem Krishna Chettri 
> <[email protected]>wrote:
>
>> Values will be Pushed to the Stack from left to right and Evaluated to be
>> finally printed from the Stack.
>>
>>
>> On Fri, Jul 22, 2011 at 4:01 PM, rShetty <[email protected]> wrote:
>>
>>> #include<stdio.h>
>>>
>>>  int main()
>>>  {
>>>
>>> int i=1;
>>> printf("%d%d%d%d",++i,++i,++i,i++);
>>>
>>>  return 0;
>>>
>>> }
>>>
>>> Explain how it will be evaluated ?? and the output obtained ..
>>>
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>
>
>
> --
> Regards
> Rajeev N B <http://www.opensourcemania.co.cc>
>
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