@ shady:the algo posted by naveen ms is better than eulicd algorithm
to find gcd. for more details refer
http://en.wikipedia.org/wiki/Binary_GCD_algorithm

On Sat, Jul 23, 2011 at 5:20 PM, shady <[email protected]> wrote:
> gcd can always be found in O(log(larger number)) using Euclidean algorithms
> , couldn't understand the complexity in that ???? what's the meaning of
> O(log UV)^2 ?
>
> On Sat, Jul 23, 2011 at 5:14 PM, dilip makwana <[email protected]>
> wrote:
>>
>> @Akshata Sharma
>>
>> (2) double full(double a)
>> {
>>    return (int)(a+0.5);
>> }
>>
>> I tried this on DevC++ , with various inputs ; it is working fine ....
>>
>> On 23 July 2011 17:00, Akshata Sharma <[email protected]> wrote:
>>>
>>> What about (2)?, will it always work?
>>>
>>> On Sat, Jul 23, 2011 at 3:13 AM, prasanth <[email protected]>
>>> wrote:
>>>>
>>>>
>>>> the CFG was actually
>>>> s->AB
>>>> A-> a| BaB
>>>> B->bbA
>>>>
>>>> The false statement i guess was "This grammar doesnt produce a string
>>>> of 4 consecutive bs"
>>>>
>>>>
>>>> and 2 or 3 questions mainly focused on j&=j-1 guess this unsets the
>>>> rightmost set bit
>>>>
>>>>
>>>> pointer related questions were asked.One such was
>>>>
>>>> (1)int arr[2][3]={{1,2,3},{4,5,6}};
>>>> int (*ptr)[3]=&a[0];
>>>> printf("(%d,%d)",(*ptr)[1],(*ptr)[2]);
>>>> ptr+=1;
>>>> printf("(%d,%d)",(*ptr)[1],(*ptr)[2]);
>>>>
>>>> find the output???
>>>>
>>>> (2) double full(double a)
>>>> {
>>>>    return (int)(a+0.5);
>>>> }
>>>>
>>>> does this always work??
>>>>
>>>> (3) int x=123,y=231;
>>>>    int t=0;
>>>>    int l;
>>>>    l=x^y;
>>>>    while(l)
>>>>    {
>>>>        t++;
>>>>        l&=l-1;
>>>>    }
>>>>    printf("%d",t);
>>>>
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>>>
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>>
>>
>>
>> --
>> Dilip Makwana
>> VJTI
>> BTech Computers Engineering
>> 2009-2013
>>
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