Will not it depend on whether the machine is big or little endian?

On Mon, Jul 25, 2011 at 11:50 AM, rajeev bharshetty <[email protected]>wrote:

> 257 is stored as
>                                     B          A
> 00000000 00000000 00000001 00000001
>
> So iptr if int* will be pointing to this above
>
> So if we typecast it as char* then it will point to 00000001 (A)
> and *ptr+1 will point to 00000001(B)
>
> Hope this clear .
>
>
> On Mon, Jul 25, 2011 at 11:41 AM, aditya kumar <
> [email protected]> wrote:
>
>> main()
>> {
>> int i = 257;
>> int *iPtr = &i;
>> printf("%d %d", *((char*)iPtr), *((char*)iPtr+1) );
>> }
>>
>> can any one explain me the o/p ??
>>
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>
>
>
> --
> Regards
> Rajeev N B <http://www.opensourcemania.co.cc>
>
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