Thank u aditi now I got it........since i m considering z=+x<y is one common
term ,silly mistake.......Thank u very much..

On Wed, Jul 27, 2011 at 10:18 PM, aditi garg <[email protected]>wrote:

> C i guess ur comfortable wid the frst 3...
> now in fourth c the order of evaluation frst x<y is evaluated as <  has
> higher precedence that +=...since both r 3...so condition is false and y++
> is taken...so z+=y++ takes place...
> z ws 1 and y=3...so z becomes 4 and it is printed... and after this y
> becomes 4... and since x++ ws not evaluated it retains its value of 3...
> in the next one z>=y takes place frst( associativity of >= is left to
> right) ,since it is true it become 1 now 1>=x is false hence ans 0...
> in the last both z>=y and y>=x are true hence 1
> i hope it is clear...
>
>
> hence the ans 3 4 4 fr the next printf
>
> On Wed, Jul 27, 2011 at 9:33 PM, Vijay Khandar <[email protected]>wrote:
>
>> #include<stdio.h>
>> #include<conio.h>
>> void main()
>> {
>> clrscr();
>> int x=1,y=1,z=1;
>> x+=y+=z;
>> printf("\n %d\n ",x<y?y:x);
>> printf("\n %d\n",x<y?x++:y++);
>> printf("\n %d %d\n",x,y);
>> printf("\n %d\n",z+=x<y?x++:y++);
>> printf("\n %d %d %d\n",x,y,z);
>> x=3;y=z=4;
>> printf("\n %d\n",z>=y>=x?1:0);
>> printf("\n %d\n",z>=y&&y>=x);
>> getch();
>> }
>>
>> I m getting o/p as--
>> 3
>> 2
>> 3 3
>> 4
>> 3 4 4
>> 0
>> 1
>>
>>  I m confusing fm fourth printf...plz explain me..........
>>
>> Vijay.............
>>
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>
>
> --
> Aditi Garg
> Undergraduate Student
> Electronics & Communication Divison
> NETAJI SUBHAS INSTITUTE OF TECHNOLOGY
> Sector 3, Dwarka
> New Delhi
>
> 9718388816
>
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