x^(x^x) - (x^x)^x = 0
Thus, x^(x^x) = (x^x)^x
Let's open it up by taking log on both sides...
(x^x)*log(x) = x* log(x^x)
(x^x)*log(x) = x*x*log(x)
If x==1 equation is satisfied as log(x) becomes 0..
so x=1 is definitely a solution. what if when x != 1
cancelling log(x) on both the sides..
x^x = x^2
Taking log on both sides..
x*log(x) = 2*log(x)
As x !=1 we can cancel log(x) on both the sides to get
x = 2 ....
Thus, final solution is {1,2}
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