hw will u get the ans on repeated subtraction from the sum of the digits??
I mean ....if I hv 2 divide 27 by 3 thn first I'll find sum of the digits
i.e, 2+7=9
then I'll apply repeated subtraction on 9, so hw will i reach to the ans??


On Sat, Jul 30, 2011 at 10:05 AM, nivedita arora <
[email protected]> wrote:

>
> @brijesh-
> itoa basically converts integer to string ..we are using the fact tht
> a number is multiple of 3 if its sum is multiple of 3
> . we have int as string and we can traverse it ..for each character
> apply
>  int sum+=*c-'0' (ankur missed the star :P)
> then on sum we use repeated subtraction...i hope its clear .
>
> we are using all this just coz we have to use itoa ..otherwise there
> are more methods (check my frst post )
>
>
> On Jul 30, 4:34 am, brijesh <[email protected]> wrote:
> > @ankur I didnt get this... could u or anyone please elaborate!
> >
> > On Jul 30, 12:43 am, Ankur Khurana <[email protected]> wrote:
> >
> >
> >
> >
> >
> >
> >
> > > when you use itoa , what you get is a string. get the sum of all the
> digits
> > > , using c-'0' and then use repeated subtraction . . .
> >
> > > On Sat, Jul 30, 2011 at 1:01 AM, sukhmeet singh <
> [email protected]>wrote:
> >
> > > > repeated subtraction !!
> >
> > > > On Sat, Jul 30, 2011 at 12:52 AM, nivedita arora <
> > > > [email protected]> wrote:
> >
> > > >> Without using /,% and * operators. write a function to divide a
> number
> > > >> by 3. itoa() function is available.
> >
> > > >> all i cn thnk of is to use shift operator and addition ,
>  x/3=e^(logx-
> > > >> log3) or repetitive subtraction
> >
> > > >> but none of them uses itoa() ..ne idea how its done?
> > > >> thnks !
> >
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> > > Ankur Khurana
> > > Computer Science
> > > Netaji Subhas Institute Of Technology
> > > Delhi.
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