if ( x&(x-1)==0 )
then number is of forn 2^n
else
false
put a separate check for x=0 as the above will not work for x=0
explanation-
take x = 8 =1000
x-1 = 7 =111
clearly x&(x-1) is 0
similarly do for a number which is not 2^n....
hope this helps !!
--
Amol Sharma
Third Year Student
Computer Science and Engineering
MNNIT Allahabad
On Sat, Jul 30, 2011 at 12:01 PM, tech rascal <[email protected]>wrote:
> thanx for the explanation saurabh....
>
>
> On Sat, Jul 30, 2011 at 11:54 AM, ankit sambyal <[email protected]>wrote:
>
>> If x is the number which is to be checked,
>>
>> if (x && !(x & (x-1)) == 0)
>> then power of 2
>>
>>
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