@gaurav- &a takes you to the address 1st element of the array.
&a+1 takes you to the next address after the last element. this mean if int
is 4bits. then arrays of 5 int values is 20 bits. so *+1 *in &a+1 covers 20
bits in memory. similarly &a+2 covers next 20 bits. and so on.

where as &(*(a+1)) points to 1st element,&(*(a+2)) points to 2nd element and
so on.

i hope this helps

On Sun, Jul 31, 2011 at 1:35 AM, gaurav gupta <[email protected]> wrote:

> so u mean der is difference between a and a[0]
>
>
> On Sun, Jul 31, 2011 at 1:30 AM, Kamakshii Aggarwal <[email protected]
> > wrote:
>
>> &a points to the array.so when u increment it by 1 it will get incremented
>> by the size of array.
>>
>>
>> On Sun, Jul 31, 2011 at 1:28 AM, gaurav gupta <[email protected]>wrote:
>>
>>> &a+1 takes to the last element of the array bt is the logic behind dis
>>>
>>>
>>> On Sun, Jul 31, 2011 at 1:25 AM, Kamakshii Aggarwal <
>>> [email protected]> wrote:
>>>
>>>> &a+1 will point to the next array(i.e it will skip the whole array)
>>>> where as &(a+1)will print address of element 2.
>>>>
>>>> On Sun, Jul 31, 2011 at 1:21 AM, Sanchit Manchanda <
>>>> [email protected]> wrote:
>>>>
>>>>> Sorry my bad. I was wrong.
>>>>>
>>>>> On Sun, Jul 31, 2011 at 1:15 AM, gaurav gupta 
>>>>> <[email protected]>wrote:
>>>>>
>>>>>> main()
>>>>>> {
>>>>>> int a[5]={1,2,3,4,5};
>>>>>> printf("%d%d",&a+1,&(a+1));
>>>>>> }
>>>>>> plz explain me the difference in ans.
>>>>>> thanx......
>>>>>>
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>>>>>
>>>>>
>>>>>
>>>>> --
>>>>> Sanchit Manchanda
>>>>> COE(3rd year) , NSIT
>>>>> http://iblogmythots.wordpress.com/
>>>>>
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>>>> Regards,
>>>> Kamakshi
>>>> [email protected]
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>> Kamakshi
>> [email protected]
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-- 
Sanchit Manchanda
COE(3rd year) , NSIT
http://iblogmythots.wordpress.com/

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