Thanks Abhishek, but I am not looking for an iterative solution.  I am
looking for a formula, if possible.

On Aug 1, 11:28 am, Abhishek Gupta <[email protected]> wrote:
> Subtract n-1,(n^2) - 1,(n^3)-1 until index is <= 0 and so on from the given
> index.
> i think following code should work. correct me if m wrong
>
> n=no. of childs in tree.
> depth=0;
> while(index>0)
> {
>     index=index - (n-1);
>     pow=pow*n;
>     depth++;
>
>
>
>
>
>
>
>
>
> }
> On Mon, Aug 1, 2011 at 3:01 PM, Douglas <[email protected]> wrote:
> > I have a full n-ary tree with N nodes.  The top node is indexed 0 with
> > all other nodes indexed incrementally from left to right as we decend
> > the tree.  The last node has index N-1.  For example, a 15 node binary
> > tree would be indexed as follows:
>
> > 0
> > 1,2
> > 3,4,5,6
> > 7,8,9,10,11,12,13,14
>
> > So, my question is, for any full n-ary tree with total nodes N, given
> > an arbitrary node index based on this structure, can I determine the
> > nodes depth in the tree?  I don't want to have to create a tree
> > structure and traverse it to determine its depth as the tree may
> > potentially be huge.  I am hoping to model this structure on the fly
> > with the availability of an analytical formula, but I am not convinved
> > it is possible?
>
> > Thanks,
>
> > Douglas.
>
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> --
> Abhishek Gupta
> MCA
> NIT Calicut
> Kerela

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