@gopi
can u explain yr tree creation ? I mean u insert the element in the tree if
u see it first, then u remove it from the tree if it has already been
inserted?( which also means u need to find the element in the tree ?) so if
an element is repeated 3 times and another 2 times what is the logic u r
trying to convey? I am sorry if i got it all wrong the way I have
interpreted it..

On Mon, Aug 1, 2011 at 8:43 PM, *$* <[email protected]> wrote:

> sorry abhishek , I have given wrong complexity for Q2.
>
>
> On Mon, Aug 1, 2011 at 12:36 PM, Abhishek Gupta <[email protected]>wrote:
>
>> @gopi
>> inserting n elements, and then again checking each element?
>> nlogn??
>>
>>
>> On Sun, Jul 31, 2011 at 9:04 PM, Anika Jain <[email protected]>wrote:
>>
>>> @gopi: in 2nd of urs we after tree creation we will need to search each
>>> element in array that will take o(nlogn) time.. is there any appraoch tht
>>> reduces this?
>>>
>>>
>>> On Sun, Jul 31, 2011 at 6:39 PM, *$* <[email protected]> wrote:
>>>
>>>>
>>>>
>>>> Q1->Construct a binary tree , in such a way that if element occured for
>>>> the first time , insert into tree , if occurs at second time , remove from
>>>> the list.
>>>> As all elements except the one need to find are even , at the end of the
>>>> list , all the tree will contain only one element.
>>>>
>>>> Q2-> Construct a binary tree. similar to the above.
>>>> Now again start from first element and check which element is missing in
>>>> the tree. That is the required one.
>>>>
>>>>
>>>> Thx,
>>>> --Gopi
>>>>
>>>>
>>>> On Sun, Jul 31, 2011 at 2:07 PM, Abhishek Gupta <[email protected]
>>>> > wrote:
>>>>
>>>>> Q1-> A large size array is given. All except one element are repeated
>>>>> even no. of times and one element is repeated odd no. of times. Find that
>>>>> element. Don't use X-OR
>>>>>
>>>>> Ans -> Is there any efficient way of finding it without using sorting
>>>>> or removing duplicates or using hash tables??
>>>>>
>>>>>
>>>>>
>>>>> Q2-> Same qn is like all except one are repeated off no. of times and
>>>>> one element repeated even no. of times. find that element. (no 
>>>>> specification
>>>>> for X-OR use given)
>>>>>
>>>>> Ans-> Again, I tried it using hash table.
>>>>>
>>>>>
>>>>> --
>>>>> Abhishek Gupta
>>>>> MCA
>>>>> NIT Calicut
>>>>> Kerela
>>>>>
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>>>>>
>>>>
>>>>
>>>>
>>>> --
>>>> Thx,
>>>> --Gopi
>>>>
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>>
>>
>> --
>> Abhishek Gupta
>> MCA
>> NIT Calicut
>> Kerela
>>
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>
>
>
> --
> Thx,
> --Gopi
>
> --
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