It may create duplicate numbers while converting into base N. How
do recognize them while converting into base(N^2)??

On 2 August 2011 17:20, Harshit Kapoor <[email protected]> wrote:

> I think that we can do it by first passing through an array once and
> convert all the interger to the base N in O(N). Since all elements are in
> the range 1 to N^2 they can have atmost 3 digits.Now apply radix sort which
> will be O( dn )  where d=3 in this case .=> O(n) when done convert them back
> to decimal notation in O(N) .
> But here N must be maximum no of single digit characters representable in
> ur system.
>
> Check if possible !!!!
>
>
>
> On Tue, Aug 2, 2011 at 1:02 PM, payel roy <[email protected]> wrote:
>
>> Can you please elaborate ??
>>
>>
>> On 2 August 2011 12:38, sunny agrawal <[email protected]> wrote:
>>
>>> Radix sort is one of the solution.
>>> because this Question is in the section Radix sort in CLRS. :)
>>>
>>>
>>> On Tue, Aug 2, 2011 at 11:10 AM, Ravinder Kumar <[email protected]>wrote:
>>>
>>>> I have little thought on this :
>>>>
>>>> divide the whole array by n and store their remainder also in an array
>>>> now number in original array are in range 1-n
>>>> sort the array and when two number with same break the tie using
>>>> remainder array
>>>> recreate the array using remainder array .
>>>> --
>>>> *With Regards :*
>>>>
>>>> Ravinder Kumar
>>>> B.Tech Final Year
>>>> Computer Science and Engineering
>>>> MNNIT Allahabad
>>>>
>>>>
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>>>
>>>
>>>
>>> --
>>> Sunny Aggrawal
>>> B-Tech IV year,CSI
>>> Indian Institute Of Technology,Roorkee
>>>
>>>
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