sizeof is not a function. The inside content in sizeof() cannot be compiled
during the compiling time, It will be replaced with the type. For example,
compiler will replace the code as j = 4;
So ++i does not execute.
On Aug 3, 2011, at 6:12 PM, brijesh wrote:
> main()
> {
> int i,j;
> i=10;
> j=sizeof(++i);
> printf("%d",i);
> }
>
> please give the output with explanation!
>
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