(10b+a)-(10a+b)=[(100b+a)or(100a+b)]-(10b+a)... [uniform speed] where a,b are natural numbers less than 10...
*1st case* 9(b-a)=90b a=-9b...not acceptable *2nd case* 9(b-a)=99a-9b b-a=11a-b b=6a...acceptable and only value which abides by the condition a,b are natural numbers less than 10 is a=1,b=6.... therefore,number is 16...avg speed is equal to 61-16=45 On Wed, Aug 3, 2011 at 7:25 PM, <[email protected]> wrote: > > first milestone 16 > second milestone 61 > third milestone 106 > > its an observation..ntn like nethn..onli thing i tht ws dat as speed is uniform so distance traveled per hr is constant..so two milestones with reverse numbers wil hv difference as 9x-9y i.e multiple of 9..also third milestone wil be very near to 100 to so 1 is fixed as a digit..odrs can be found out by hit and trial.. > > VM > NSIT, COE, 3rd year > > On , Kamakshii Aggarwal <[email protected]> wrote: > > vaibhav can u please explain.i know the answer already..i m just not able to solve the equations fully > > > > On Wed, Aug 3, 2011 at 7:09 PM, Arun Vishwanathan [email protected]> wrote: > > > > in general, if u guys get any answer, please post a short explanation even if it the solution is very obvious to u...not everyone gets it when looking at the answer... > > > > > > > > > > On Wed, Aug 3, 2011 at 3:34 PM, [email protected]> wrote: > > > > 45 km/hr > > > > VM > > NSIT, COE, 3rd year > > > > > > > > > > > > On , Kamakshii Aggarwal [email protected]> wrote: > > > A car is traveling at a uniform speed.The driver sees a milestone showing a 2-digit number. After traveling for an hour the driver sees another milestone with the same digits in reverse order.After another hour the driver sees another milestone containing the same two digits. What is the average speed of the driver? > > > > > > > > > > > > > > > > > > > > > > > > > > > > -- > > > > > > You received this message because you are subscribed to the Google Groups "Algorithm Geeks" group. > > > > > > To post to this group, send email to [email protected]. > > > > > > > > > > To unsubscribe from this group, send email to [email protected]. > > > > > > > > > For more options, visit this group at http://groups.google.com/group/algogeeks?hl=en. > > > > > > > > > > > > > > > > > > > > -- > > You received this message because you are subscribed to the Google Groups "Algorithm Geeks" group. > > To post to this group, send email to [email protected]. > > > > > > To unsubscribe from this group, send email to [email protected]. > > For more options, visit this group at http://groups.google.com/group/algogeeks?hl=en. > > > > > > > > > > > > > > > > > > > > > > > > > > > > > > > > > > -- > > > > You received this message because you are subscribed to the Google Groups "Algorithm Geeks" group. > > > > To post to this group, send email to [email protected]. > > > > To unsubscribe from this group, send email to [email protected]. > > > > > > For more options, visit this group at http://groups.google.com/group/algogeeks?hl=en. > > > > > > > > > > > > > > > > > > -- > > Regards, > > Kamakshi > > [email protected] > > > > > > > > > > > > -- > > > > You received this message because you are subscribed to the Google Groups "Algorithm Geeks" group. > > > > To post to this group, send email to [email protected]. > > > > To unsubscribe from this group, send email to [email protected]. > > > > > > For more options, visit this group at http://groups.google.com/group/algogeeks?hl=en. > > > > > > > > > > -- > You received this message because you are subscribed to the Google Groups "Algorithm Geeks" group. > To post to this group, send email to [email protected]. > To unsubscribe from this group, send email to [email protected]. > For more options, visit this group at http://groups.google.com/group/algogeeks?hl=en. -- Thanks & Regards Abhishek Iyer "If You Obey All the Rules, You Will Miss All the Fun. " -- You received this message because you are subscribed to the Google Groups "Algorithm Geeks" group. To post to this group, send email to [email protected]. To unsubscribe from this group, send email to [email protected]. For more options, visit this group at http://groups.google.com/group/algogeeks?hl=en.
