@amol knapsack is originaly a greedy problem only!!!!!!!!The spirit remains
the same,selecting the best at each step....Dp helps in defining the best in
  the particular case.
@Gaurav I think its NP complete once the number of teams become
varaible,,,,,
corrct me if wrong i am weak with the theoritical stuffs...

On Thu, Aug 4, 2011 at 8:06 PM, Amol Sharma <[email protected]> wrote:

> @gaurav: agree...greedy wouldn't work in this case......even 0-1 knapsack
> is a DP problem...which can't be done by greedy !!
> --
>
>
> Amol Sharma
> Third Year Student
> Computer Science and Engineering
> MNNIT Allahabad
>
>
>
>
> On Thu, Aug 4, 2011 at 7:46 PM, Gaurav Menghani <[email protected]
> > wrote:
>
>> On Thu, Aug 4, 2011 at 7:42 PM, Gaurav Menghani
>> <[email protected]> wrote:
>> >
>> > On Thu, Aug 4, 2011 at 7:37 PM, saurabh singh <[email protected]>
>> wrote:
>> >>
>> >> Its a classical 0/1 knapsack problem which can be implemented either as
>> a
>> >> greedy solution or dp,,,,
>> >
>> > It has been stated earlier in the thread that this is an 'NP-Complete'
>> > problem. [0]
>> > It means, there is no known polynomial-time algorithm for this problem.
>> If
>> > you think you have a greedy solution to this problem, think again. The
>> DP
>> > solution is also, 'pseudo-polynomial-time'
>>
>> Just adding, greedy solutions are always possible, but the thing to
>> ponder over is, whether they give optimal solutions _for_every_case_
>> or not.
>>
>>
>> --
>> Gaurav Menghani
>>
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-- 
Saurabh Singh
B.Tech (Computer Science)
MNNIT ALLAHABAD

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