A dice is 6 B reports 6
P(A) = 1/6 P(!A) = 5/6 P(B|!A) =(1/4)*(1/5) P(B|A) = (3/4) P(A|B) = P(B|A)*P(A)/( P(B|A)*P(A) + P(B|!A)*P(!A)) =((3/4)*(1/6))/( (3/4)*(1/6) + (1/4)*(1/5)*(5/6)) = 3/4 On Fri, Aug 5, 2011 at 4:50 PM, tarang dawer <[email protected]> wrote: > 1/2 > > > > -- > You received this message because you are subscribed to the Google Groups > "Algorithm Geeks" group. > To post to this group, send email to [email protected]. > To unsubscribe from this group, send email to > [email protected]. > For more options, visit this group at > http://groups.google.com/group/algogeeks?hl=en. > -- You received this message because you are subscribed to the Google Groups "Algorithm Geeks" group. To post to this group, send email to [email protected]. To unsubscribe from this group, send email to [email protected]. For more options, visit this group at http://groups.google.com/group/algogeeks?hl=en.
