i see but is not arr a pointer to first array element and so &arr contain
address of that pointer ?

On Fri, Aug 5, 2011 at 4:06 PM, Vijay Khandar <[email protected]>wrote:

> I dont think so dp=&arr;   since **dp; dp contains the addr of another ptr
> variable...
>
>   On Fri, Aug 5, 2011 at 7:27 PM, Arun Vishwanathan <
> [email protected]> wrote:
>
>>
>> I guess someone had posted a link earlier from which I have a basic doubt
>>
>> when u have
>>
>> int arr[3]={1,0,2};
>> int **dp;
>> int (*pa)[3];
>>
>> is this the right assingment for instance?
>>
>> pa=arr;
>> dp=&arr;
>>
>> or have I flipped the ampersand in assigning?
>>
>> Also when I do pa++ will it jump by size of int or the whole array size it
>> points to?
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