Store the frequency of all the letters in an array in one scan(like counting
sort). In the next pass remove the duplicates and appropriately shift .
takes 2 O(n) passes i guess....

On Fri, Aug 5, 2011 at 4:50 PM, priya v <[email protected]> wrote:

>
> Remove duplicate alphabets from a string and compress it in the same
> string. For
> example, MISSISSIPPI becomes MISP. O (n2) is not acceptable.
> For this problem is it a good idea to sort the array using a sorting
> technique with efficiency O(nlogn)
> and remove the duplicates?
>
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-- 
S.Nishaanth,
Computer Science and engineering,
IIT Madras.

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