On 6 August 2011 23:40, aditi garg <[email protected]> wrote:

> A[3][4] wud be in the 4th row...so strtung address of 4th row wud be
> 46..and thn 4th element wud be at 49...similarly fr B 180 fr the frst 3 rows
> + 16 fr the 4th elemnet so 196
>

How does it start from 46 and 180 ?
as per my knowledge, 0x1000 = 4096 and 0x2000 is 8192


>
> On Sat, Aug 6, 2011 at 11:37 PM, akshay khatri 
> <[email protected]>wrote:
>
>> how is that 49 bytes and 196 bytes
>> shouldn't it be 44 and 176 bytes respectively
>>
>>
>> On 6 August 2011 23:26, Ram Chauhan <[email protected]> wrote:
>>
>>> 1049 and 1098
>>>
>>> On Sat, Aug 6, 2011 at 11:09 PM, aditi garg 
>>> <[email protected]>wrote:
>>>
>>>> CHAR A[10][15] AND INT B[10][15] IS DEFINED
>>>> WHAT'S THE ADDRESS OF A[3][4] AND B[3][4]
>>>> IF ADDRESS OF A IS OX1000 AND B IS 0X2000
>>>>
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>
>
> --
> Aditi Garg
> Undergraduate Student
> Electronics & Communication Divison
> NETAJI SUBHAS INSTITUTE OF TECHNOLOGY
> Sector 3, Dwarka
> New Delhi
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