simple manipulation
ans = max( (smallest negative number 1 * smallest negative number 2 *
largest positive number 1), (largest positive number 1, largest positive
number 2, largest positive number 3) )

On Sun, Aug 7, 2011 at 7:04 PM, Prakash D <[email protected]> wrote:

> that won't work.. there may be two negative bigger numbers whose product
> will bcom +ve
>
>
> On Sun, Aug 7, 2011 at 6:49 PM, Puneet Ginoria <[email protected]>wrote:
>
>> find the first three largest nos. and 3 smallest number(negatives).. then
>> easily you can fig. out the solution..
>>
>> O(6n) solution i guess which is O(n)....
>>
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