Even u dont get why u people are gettin 17/80...the probability that
it will be a head 6th time will be same as the frst time...so it shud
be 3/5...

On Aug 7, 11:05 pm, Kunal Yadav <[email protected]> wrote:
> @algo: We can get head in two cases:-
>
> 1.) coin is biases
> 2.) coin is not biased
>
> P(head) for biased= 1/5 *1*1*1*1*1*1= 1/5
> P(head) for unbiased= 4/5*(1/2)^6
> hence combined probability is what nitish has already mentioned. Hope you
> get the point.
>
>
>
>
>
>
>
>
>
> On Sun, Aug 7, 2011 at 11:29 PM, Algo Lover <[email protected]> wrote:
> > Can anyone explain the approach how to solve this .
> > I think all tosses are independent so it should be 3/5. why is this in-
> > correct
>
> > On Aug 7, 10:55 pm, saurabh chhabra <[email protected]> wrote:
> > > sry...its wrong
>
> > > On Aug 7, 10:34 pm, Algo Lover <[email protected]> wrote:
>
> > > > A bag contains 5 coins. Four of them are fair and one has heads on
> > > > both sides. You randomly pulled one coin from the bag and tossed it 5
> > > > times, heads turned up all five times. What is the probability that
> > > > you toss next time, heads turns up. (All this time you don't know you
> > > > were tossing a fair coin or not).
>
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> --
> Regards
> Kunal Yadav
> (http://algoritmus.in/)

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