if the hash function evaluates to 3 or 4 , collision occurs and by linear
probing they are put into 5(nearest free entry). Also 5 and 6 are empty.

But if the hash value points to 7,8,9,10 or 1 , they will be put into
2(nearest free entry).

On Thu, Aug 11, 2011 at 10:53 PM, Mani Bharathi <[email protected]>wrote:

> how do u say that they will lead to 2?
>
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