&a[4]-&a[0] is interpreted as &*(a+4)-&*(a+0) which is actually (a+4)- (a+0)=4 thats wat i think because array is converted to pointer notation during compilation
On Aug 12, 11:04 am, rohit <[email protected]> wrote: > int main() > { > int a[5]={1,2,3,4,5}; > printf("%d",&a[4]-&a[0])} > > why it show 4 not 16? -- You received this message because you are subscribed to the Google Groups "Algorithm Geeks" group. To post to this group, send email to [email protected]. To unsubscribe from this group, send email to [email protected]. For more options, visit this group at http://groups.google.com/group/algogeeks?hl=en.
