@$ did not understand how the original array is sorted to give the number!

On Sat, Aug 13, 2011 at 12:50 PM, *$* <[email protected]> wrote:
> 1.scan the array and find the maximum digits of integer. lets say m..
> 2.Again scan the array and pad the intergers whose digits are less that m (<
> m) with zero's .. copy the new integers in a new array
> 3.sort the new array in desc order and carry the same even for original
> array.
> 4. Now the original array contains the required output.
> ex: original aarray 23,8,19,9,1
>
> max digits : 2 (for 23 as well as 19)
> step 2: new array 23,80,19,90,10
> step3. sort .. 90,80,23,19,10 .. and corresponding original is .. 98231910.
>
> original array contains the original output..
>
>
>
> On Sat, Aug 13, 2011 at 7:15 AM, chengjie qi <[email protected]> wrote:
>>
>> int compare(int a, int b) {
>> string s = Integer.tostring(a);
>> string y = Integer.tostring(b);
>> if (s +y < y+s)
>>    return -1;
>> else
>>    return 1;
>> }
>>
>>  use this to write quick sort , you can get the answer.
>> On Fri, Aug 12, 2011 at 8:34 PM, Yasir Imteyaz <[email protected]>
>> wrote:
>>>
>>> An array of integers is given and you have to find the largest possible
>>> integer by concatenating all elements:
>>> example:
>>> array:  87  36  52
>>> answer:  875236
>>> array: 87 9 52
>>> answer: 98752
>>>
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>>
>>
>>
>> --
>> stay hungry stay foolish
>> Chengjie Qi
>>
>>
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>
>
>
> --
> Thx,
> --Gopi
>
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