For the first ques the output will be have fun...have fun...have fun...have
fun...have fun...
dis is because printf will not take into consideration \n because of its
format...unless and untill we do not write sm %d or %s or %u etc it wont
access the portion of the statement after comma operator...
i hope it is clear...

On Mon, Aug 15, 2011 at 1:40 PM, Anil Arya <[email protected]> wrote:

> a##b means you are using the value of ab whatever the value of a and b is
> given.
>
>
> On Mon, Aug 15, 2011 at 1:13 PM, Sanjay Rajpal <[email protected]>wrote:
>
>> ## is used for concatenation in C.
>>
>>
>>
>> On Mon, Aug 15, 2011 at 12:40 AM, Nitin <[email protected]> wrote:
>>
>>> #include<stdio.h>
>>> #define fun(arg) do\
>>> {\
>>>         if(arg)\
>>>         printf("have fun...","\n");\
>>> }while(i--)
>>>
>>> main()
>>> {
>>>         int i=6;
>>>         fun(i<5);
>>> }
>>>
>>> give the answer and please give the reason for this
>>>
>>> #include<stdio.h>
>>> #define fun(a,b) a##b
>>>  main()
>>> {
>>>         int a, b, ab;
>>>         a = 1, b = 2, ab = 3;
>>>         printf("%d %d", fun(a,b), ab);
>>>         return -1;
>>>
>>> }
>>> please tell me the use of this # in this program
>>> ~
>>>
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>>
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>
>
>
> --
> Anil Kumar Arya
> B.Tech  III year
> computer science & engineering
> M.N.N.I.T Allahabad.
>
>
>
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-- 
Aditi Garg
Undergraduate Student
Electronics & Communication Divison
NETAJI SUBHAS INSTITUTE OF TECHNOLOGY
Sector 3, Dwarka
New Delhi

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