On 15 August 2011 21:07, sagar pareek <[email protected]> wrote:

> int lol=2; // total lol's encountered upto now
>
> lol++;


it is a programming mistake as you have indicated the value of the important
variable constant lol to 2 and then you have incremented it. :P


>
>
> On Mon, Aug 15, 2011 at 12:41 AM, aditi garg <[email protected]>wrote:
>
>> lol
>>
>>
>> On Mon, Aug 15, 2011 at 12:40 AM, aditya kumar <
>> [email protected]> wrote:
>>
>>> @aditi : sry i dint realise that n > log n .:P
>>>
>>> On Mon, Aug 15, 2011 at 12:38 AM, aditi garg 
>>> <[email protected]>wrote:
>>>
>>>> @aditya : dis is obviously correct bt here complexity will be O(n) bt we
>>>> are asked to gv O(log n) solution
>>>>
>>>> On Mon, Aug 15, 2011 at 12:37 AM, aditya kumar <
>>>> [email protected]> wrote:
>>>>
>>>>> for(j=0;j<n;j++)
>>>>> {
>>>>> if(a[j]==j)
>>>>>  return j;
>>>>>  else
>>>>>  continue ;
>>>>> }
>>>>>
>>>>> this shud also be correct right ??
>>>>>
>>>>> On Mon, Aug 15, 2011 at 12:31 AM, Akash Mukherjee 
>>>>> <[email protected]>wrote:
>>>>>
>>>>>> just my 2 cents ---- in d binary search, replacing key with mid, ie
>>>>>> if(a[mid] > mid)
>>>>>> check lower half
>>>>>> else upper half
>>>>>>
>>>>>> should work??
>>>>>>
>>>>>>
>>>>>> On Mon, Aug 15, 2011 at 12:26 AM, aditi garg <
>>>>>> [email protected]> wrote:
>>>>>>
>>>>>>> Given an ordered array A[1…n] with numbers in strictly increasing
>>>>>>> order. Find a ‘j’ such that A [j]=j or -1 if no such number exist in
>>>>>>> o (log n).
>>>>>>>
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>>>>
>>>>
>>>>
>>>> --
>>>> Aditi Garg
>>>> Undergraduate Student
>>>> Electronics & Communication Divison
>>>> NETAJI SUBHAS INSTITUTE OF TECHNOLOGY
>>>> Sector 3, Dwarka
>>>> New Delhi
>>>>
>>>>
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>>>
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>>
>>
>>
>> --
>> Aditi Garg
>> Undergraduate Student
>> Electronics & Communication Divison
>> NETAJI SUBHAS INSTITUTE OF TECHNOLOGY
>> Sector 3, Dwarka
>> New Delhi
>>
>>
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>
>
>
> --
> **Regards
> SAGAR PAREEK
> COMPUTER SCIENCE AND ENGINEERING
> NIT ALLAHABAD
>
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-- 
Regards
Siddharth Srivastava

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